Inserting a node at the nth position

suggest change

So far, we have looked at inserting a node at the beginning of a singly linked list. However, most of the times you will want to be able to insert nodes elsewhere as well. The code written below shows how it is possible to write an `insert()` function to insert nodes anywhere in the linked lists.

```#include <stdio.h>
#include <stdlib.h>

struct Node {
int data;
struct Node* next;
};

struct Node* insert(struct Node* head, int value, size_t position);

int main(int argc, char *argv[]) {
struct Node *head = NULL; /* Initialize the list to be empty */

/* Insert nodes at positions with values: */

return 0;
}

struct Node* insert(struct Node* head, int value, size_t position) {
size_t i = 0;
struct Node *currentNode;

/* Create our node */
currentNode = malloc(sizeof *currentNode);
/* Check for success of malloc() here! */

/* Assign data */
currentNode->data = value;

/* Holds a pointer to the 'next' field that we have to link to the new node.
By initializing it to &head we handle the case of insertion at the beginning. */
/* Iterate to get the 'next' field we are looking for.
Note: Insert at the end if position is larger than current number of elements. */
for (i = 0; i < position && *nextForPosition != NULL; i++) {
/* nextForPosition is pointing to the 'next' field of the node.
So *nextForPosition is a pointer to the next node.
Update it with a pointer to the 'next' field of the next node. */
nextForPosition = &(*nextForPosition)->next;
}

/* Here, we are taking the link to the next node (the one our newly inserted node should
point to) by dereferencing nextForPosition, which points to the 'next' field of the node
that is in the position we want to insert our node at.
We assign this link to our next value. */
currentNode->next = *nextForPosition;

/* Now, we want to correct the link of the node before the position of our
new node: it will be changed to be a pointer to our new node. */
*nextForPosition = currentNode;

}

void print_list (struct Node* head) {
/* Go through the list of nodes and print out the data in each node */
while (i != NULL) {
printf("%d\n", i->data);
i = i->next;
}
}```

Feedback:
Optional: your email if you want me to get back to you: